a = 0 count = 0 sz = [] num = 0 while a < 100: a += 1 if a%7 == 0: sz.append(a) count += 1 print("7的倍数是:",a) for i in range(len(sz)): num += sz[i] print("100之内有%s个奇数,全部奇数的和是%s"%(count,num))
输出结果:app
7的倍数是: 7
7的倍数是: 14
7的倍数是: 21
7的倍数是: 28
7的倍数是: 35
7的倍数是: 42
7的倍数是: 49
7的倍数是: 56
7的倍数是: 63
7的倍数是: 70
7的倍数是: 77
7的倍数是: 84
7的倍数是: 91
7的倍数是: 98
100之内有14个奇数,全部奇数的和是735ide
转载于:https://blog.51cto.com/3945465/2373824code