开发中常常须要比较时间，写了一个简易的工具类，分享一下：java
?ide
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package
com.ijiuyuan.common.utils;
import
java.text.ParseException;
import
java.text.SimpleDateFormat;
import
java.util.Calendar;
import
java.util.Date;
public
class
DiffTime {
public
static
void
main(String[] args){
SimpleDateFormat sdf=
new
SimpleDateFormat(
"yyyy-MM-dd HH:mm:ss"
);
Date startTime =
null
;
Date endTime =
null
;
try
{
startTime = sdf.parse(
"2014-06-24 10:19:40"
);
endTime=sdf.parse(
"2014-06-16 10:19:40"
);
}
catch
(ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
long
nd =
1000
*
24
*
60
*
60
;
// 一天的毫秒数
long
md =
1000
*
1
*
1
*
60
;
// 分钟的毫秒数
long
sd =
1000
*
1
*
1
*
1
;
// 毫秒数
long
diff =startTime.getTime()-
new
Date().getTime() ;
long
day = diff / nd;
// 计算差多少天
long
minute=diff/md;
long
second=diff/sd;
System.out.println(second);
if
(diff>=nd*
7
){
System.out.println(
"预备中:"
+second);
}
long
endday = (endTime.getTime()-
new
Date().getTime()) / md;
// 计算差多少天
System.out.println(endday);
if
(day <=
7
&& day >=
0
) {
if
(minute>=
0
)
System.out.println(
"即将开始"
);
else
{
System.out.println(
"已结束"
);
}
}
else
if
(day >
7
) {
System.out.println(
"预备中"
);
}
else
{
System.out.println(
"已结束"
);
}
}
/**
* 时间比较
* <p>
* 若是第一个时间大于第二时间返回1<br/>
* 等于返回0<br/>
* 小于返回-1
* </p>
* @param firstTime
* @param secondTime
* @return
*/
public
static
int
compare(Date firstTime,Date secondTime){
long
diff =firstTime.getTime()- secondTime.getTime() ;
if
(diff>
0
){
return
1
;
}
else
if
(diff==
0
){
return
0
;
}
else
{
return
-
1
;
}
}
/**
* 是否值过大
* @param firstTime
* @return
*/
public
static
boolean
isTooLarge(Date firstTime){
Calendar calendar=Calendar.getInstance();
calendar.setTime(
new
Date());
calendar.add(Calendar.YEAR,
1000
);
Date bigDate=calendar.getTime();
if
(compare(firstTime, bigDate)>
0
){
return
true
;
}
else
{
return
false
;
}
}
}
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